Hello everyone. This lesson we will tell the integrate of $int frac{x}{x-1}dx$.
What is the integral of x/x-1?
![]() |
| integral of x/x-1 |
First we separate the expression.
So;
$frac{x}{x-1}=1+frac{1}{x-1}$
So our answer;
$int frac{x}{x-1}dx=int 1 dx+ int frac{1}{x-1}dx=x+ln|x-1|+C$
